hello, i dont really understand perfectly what you measuring but it sounds
like you are measuring the resistance of two wires that will be 12pos when
the ignition is turned on. my first guess is that they have some kind of
resistor in series with the cigerette lighter to reduce the current, perhaps
the lighter by its self draws too much current. also, maybe some how you are
measuring the internal resistance of the battery. are you measuring this
resistance on a live set of wires?
im guessing they have some kind of resistor in the circuit to reduce current
to the lighter.